0=5/(x-2)^2

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Solution for 0=5/(x-2)^2 equation: 


D( x )

(x-2)^2 = 0

(x-2)^2 = 0

(x-2)^2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

0 = 5/((x-2)^2) // - 5/((x-2)^2)

0-(5/((x-2)^2)) = 0

-5*(x-2)^-2 = 0

-5/((x-2)^2) = 0

-5 = 0

x belongs to the empty set

x belongs to the empty set

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